A contract on constructing job specifies a penalty for delay of completion beyond a certain date as follows : ` 15 for first day, ` 25 for second day, ` 35 for third day etc. The penalty for each succeeding day being ` 10 more than the preceding day. How much money the contractor has to pay as penalty. If he has delayed the work by 25 days?
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Step-by-step explanation:
It can be observed that these penalties are in an A.P. having first term as 200 and common difference as 50.
a=200,d=50
Sum upto n terms (S
n
)=
2
n
[2a+(n−1)d]
Penalty that has to be paid if he has delayed the work by 30 days
=S
30
= S
30
=
2
30
[2(200)+(30−1)50]
=15[400+1450]
=15(1850)
=27750
Therefore, the contractor has to pay Rs 27750 as penalty.
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