A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows. RS 200 for the first day, RS 250 for the second day, Rs 300 for third day and so on. If the contractor pays RS 27750 as penalty find the no of days for which the construction work is delayed
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Answer:
on 552nd day the amount of penalty will be 27750.
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Answer:
It can be observed that these penalties are in an A.P. having first term
as 200 and common difference as 50.
a = 200 and d = 50
Penalty that has to be paid if he has delayed the work by 30 days
= S30
= 15 [400 + 1450]
= 15 (1850)
= 27750
Therefore, the contractor has to pay Rs 27750 as penalty.
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