Question

A contract on construction job specifies a penalty for delay in completion of the work beyond a certain date is as follows: rs 200 for the first day, rs 250 for the second day, rs 300 for the third day etc, the penalty for each succeeding day being rs 50 more than that of the preceding day. How much penalty should the contractor pay if he delays the work by 10 days?

Answer 1

n=10

a=200

d=50

Sn=n/2{2a+(n-1)d}

S10=10/2{2(200)+(10-1)50}

=5{400+(9)50}

=5{400+450}

=5{850}

=4250

Answer 2

Answer:

It can be observed that these penalties are in an A.P. having first term

as 200 and common difference as 50.

a = 200 and d = 50

Penalty that has to be paid if he has delayed the work by 30 days

= S30

= 15 [400 + 1450]

= 15 (1850)

= 27750

Therefore, the contractor has to pay Rs 27750 as penalty.

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