Question

a contract on construction job specifies a penalty for delay of completion beyond a certain date as follows rupees 200 for the first day rupees 250 for the second year rupees 300 for the third day the penalty for succeeding day being Rs 50 more than the preceding day how much money the contractor has to pay as penalty if we delete the work by 30 days​

Answer 1

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Answer 2

Answer:

Rs 27750

Step-by-step explanation:

The contract specifies penalty of Rs 200 the first day .

The next day penalty is Rs 250 .

Image this as an A.P or arithmetic progression .

a = Rs 200 .

d = Rs 50

n = 30 .

Sn = n/2 [ 2 a + ( n - 1 ) d ]

⇒ Sn = 30/2 [ 2 ( 200 ) + ( 30 - 1 ) ( 50 ) ]

⇒ Sn = 15 [ 400 + 29 × 50 ]

⇒ Sn = 15 [ 400 + 1450 ]

⇒ Sn = 15 [ 1850 ]

⇒ Sn = 27750 ,

The money will be Rs 27750 .