Math, asked by saurabhsaurabh2141, 1 year ago

A contractor agreeing to finish a work in 150 days employed 75 men each working 8 hours daily. After 90 days, only 2/7 of the work was completed. Increasing the number of men by _______, each working now for 10 hours daily, and the work can be completed in time.

Answers

Answered by mohakrk2004
7

One day's work = 2 / (7 * 90)

One hour's work = 2 / (7 * 90 * 8)

One man's work = 2 / (7 * 90 * 8 * 75)


The remaining work (5/7) has to be completed within 60 days, because the total number of days allotted for the project is 150 days.So we get the


equation(2 * 10 * x * 60) / (7 * 90 * 8 * 75) = 5/7


where x is the number of men working after the 90th day.


We get x = 225


Since we have 75 men already, it is enough to add only 150 men..

Hope I got it right


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