A contractor employed 20 men to build a tank and completed it in 10 days. After working together for 3 days, 5 men go home and do not return. How many days more will the remaining men take to complete the work?
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So, 20 men complete 1/10 of the job in 1 day. So, 1 man completes (1/10)/20=0.005 of the job in 1 day.
If 20 men work at the job for 3 days, they complete 3/10 of the job, leaving 7/10 undone. If 5 men leave, 15 men continue and complete 15*0.005=0.075 of the job each day.
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