a contractor employed 210 men to build a house in 60 days. After 12 days, he was joined by 70 more men. In how many days will the remaining work be finished?
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Hi there!
Here's the answer:
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
No. of Men employed by contractor to build a house in 60 days = 210
They worked for 12 days
•°• No. of days left to finish the remaining work = 60 - 12 = 48
70 more men joined to complete the work
•°• Total No. of men = 70 + 210 = 280
Let the No. of days taken to finish the work by 280 men be x
210 Men --------- 48 days
280 Men ---------- x days
{Here,
As No. of Men increased, No. of days taken to finish the work decreases.
•°• It is a Inverse Proportion}
210 × 48 = 280 × x
=> x = (210 × 280)/48
=> x = 36 days
•°• Remaining work will be finished in 36 days
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
Hope it helps
Here's the answer:
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
No. of Men employed by contractor to build a house in 60 days = 210
They worked for 12 days
•°• No. of days left to finish the remaining work = 60 - 12 = 48
70 more men joined to complete the work
•°• Total No. of men = 70 + 210 = 280
Let the No. of days taken to finish the work by 280 men be x
210 Men --------- 48 days
280 Men ---------- x days
{Here,
As No. of Men increased, No. of days taken to finish the work decreases.
•°• It is a Inverse Proportion}
210 × 48 = 280 × x
=> x = (210 × 280)/48
=> x = 36 days
•°• Remaining work will be finished in 36 days
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
Hope it helps
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