Question

A contractor employed 210 men to build ahouse in 60 days. after 12days, he joined by 70 more men. in how i how many days will the reaminingwork be finished

Answer 1

210 men can complete the remaining work in 48 days

So,we have to find out how many days 280 men can do (210+70 more men)

=210×48/280

=36

Therefore 280 men can complete the remaining work in 36 days.

Answer 2

Given:

• 210 men were employed to build a house in 60 days.
• After 12 days, 70 more men were added.
• Total work done = 1

To Find:

• Time taken to finish remaining work.

Solution:

• Each man working for one day = $\frac{1}{210*60}$
• After 12 days,
• Total work done by 210 men in 12 days =  $\frac{1}{210*60}*210*12 = \frac{12}{6} = \frac{1}{5}$
• When 70 workers were added after 12 days, the total workers = 210+70 = 280 workers.
• Finding the remaining work to know the days required.
• Remaining work = 1-1/5 = 4/5 → (1)
• let the remaining work be completed in the next "X" days.
• To find "x", consider total work done by 280 workers = $\frac{1}{210*60} *280*X$ → (2)
• Equating (1) and (2),
• $\frac{4}{5} = \frac{280X}{12600}$
• ⇒ 1400X = 50400
• ⇒ X = 50400/1400 = 36 days.

∴Time taken to finish the remaining work by 280 workers is 36 days.