A contractor employed 30 men to do a piece of work in 38 days.After 25 days . he employed 5 men more and the work finished one day earlier. How many days he would have been behind , if he had not employed additional men?
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work=day*worker
Total work=30*38=1140
25 day work done=25*30=750
35 work done in 12 days=35*12=420
full done by both 30 +5 worker=750+420=1170
1170-1140
=30
work=day×worker
30=30×day
day=1
it's take one day more
Total work=30*38=1140
25 day work done=25*30=750
35 work done in 12 days=35*12=420
full done by both 30 +5 worker=750+420=1170
1170-1140
=30
work=day×worker
30=30×day
day=1
it's take one day more
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