Math, asked by anushkaupadhyay212, 2 months ago

A contractor employs 56 labourers to lay a road
He agrees to get the work done in 15 days. But
the authorities want the work to be completed
in 10 days. How many more men should he
employ?

Answers

Answered by turbojamir
0

Actual Part of the work done in 1 day is 1/15 (for 56 workers)

Required work to be done in 1 day is 1/10 (for x workers)

Therefore, part of the work done in 1 day ( for 1 worker)

1/15*1/56=1/10*1/x

10x=15*56(cross multiplying)

10x=840

x=84

Hope this is clear

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