Question

A contractor has some amount if he spends 20% on raw material, 25% on buildings,30% on machinery. if 12,50,000 left with him.find the amount invested on machinery?
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Answer 1

Answer:

Let the amount be x.

Then,percentage invested on machinery: 30%

Total percentage: 75%

75% of x= 12,50,000

75/100×x=12,50,000

x=12,50,000×100/75

x=12,50,00000/75 Rs.(approx)

Now, 30% of 12,50,00000/75 will give the required answer.

30/100×12,50,00000/75

500000₹.

HOPE THIS HELPS :D