Math, asked by vinod8157, 1 year ago

A contractor has the target of completing a work in 40 days .he employed 20 person who completed 1/4 of the work in 10 days and left . the number of persons he has to employs finish the remaining part as per target it​

Answers

Answered by bhagyashreechowdhury
10

Answer:

20 persons has to be employed by the contractor to finish the remaining part of the work as per target.

Step-by-step explanation:

Total work to be done in 40 days.

Work done in 1 day = (1 / 40)

Work done by 20 persons in 10 days = (10/40= (1/4)

Work done by 1 person in 1 day = (1/4) * (1/20) * (1/10) = (1/800)  

As given to us in the question, 20 persons have completed (1/4)th of the work in 10 days.

∴ Remaining days to complete the work = 40 – 10 = 30 days.

∴ Remaining work to be done = (1 – ¼)th = (3/4)th

Let the no. of persons required to complete the work in 30 days be “n”.

∴ Remaining work to be done = (no. of persons required) * (no. of days remaining) * (work done by 1 person in 1 day)

∴ ¾ = n * 30 *(1/800)

Or, n = (800 * 3) / (4 * 30)

Or, n = 20  

The no. of persons required to complete the work in 30 days is 20.

Answered by sateeshsn055
4

Answer:

Step-by-step explanation:

(20×10)/1 =(30×D)/3

D=20 days

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