Math, asked by tarachandbora6485, 2 months ago

A contractor hired 3 laboured a, b and c to paint a house. All 3 labourers a, b and c took 4 days, 6 days and 5 days. If they get 9250 for it, how much would each of them gets?

Answers

Answered by riddhirajbhattacharj
3

Answer:

Pay for labourer a = = 2466.68                                

Pay for labourer b = 3700.02                            

Pay for labourer c = 3083.35                          

Step-by-step explanation:

Since they are getting paid for their collective work:

4 days + 6 days + 5 days = 9250

15 days = 9250

1 day = 9250/15

1 day = 616.67

∴ Pay for labourer a = 4 x 616.67

                                   = 2466.68

Pay for labourer b = 6 x 616.67

                                = 3700.02

Pay for labourer c = 5 x 616.67

                               = 3083.35

Answered by kapilaaravikumar
1

answer is in the photo

hope the answer helps

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