A contractor hired 3 laboured a, b and c to paint a house. All 3 labourers a, b and c took 4 days, 6 days and 5 days. If they get 9250 for it, how much would each of them gets?
Answers
Answered by
3
Answer:
Pay for labourer a = = 2466.68
Pay for labourer b = 3700.02
Pay for labourer c = 3083.35
Step-by-step explanation:
Since they are getting paid for their collective work:
4 days + 6 days + 5 days = 9250
15 days = 9250
1 day = 9250/15
1 day = 616.67
∴ Pay for labourer a = 4 x 616.67
= 2466.68
Pay for labourer b = 6 x 616.67
= 3700.02
Pay for labourer c = 5 x 616.67
= 3083.35
Answered by
1
answer is in the photo
hope the answer helps
Attachments:
Similar questions