A contractor is entrusted to erect a tent for flood-victims. He is allowed a fixed amount for this task. He has two options :
(i) to erect a tent which is cylindrical upto a height of 3 m and conical above it. The diameter of the base is 105 m and slant height of the conical part is 53 m.
(ii) to erect the tent as described in option(i), only replacing the conical part as a hemispherical part.
The contractor chooses the option-(ii) and decides to donate the extra (difference) canvas to be used in this case.
How much canvas is donated by the contractor?
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he would not save canvas by making hemispherical type top of tent
Step-by-step explanation:
in both option cylinderical shape part is samr
hence we will find canvas used in conical and hemispherical shape.
for that we need to find curved surface areas of both
conical shape
radius = 105/2 m
slant height 53 m
curved surface area = (22/7)×(105/2) × 53
= 8745 m^2
hemispherical shape
radius = 105/2 m
curved surface area = 2*(22/7)(105/2)^2
= 17325 m^2
he would not save canvas by making hemispherical type top of tent
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