Question

A contractor undertakes to complete a work in 130 days. He employs 150 men for 25 days and they complete 1/4 of the work . He then reduces the number of men to 100, who work for 60 days, after which there are 10 days holidays.How many men must be employed for the remaining period to finish the work?​

Answer 1

Answer:

300 Men  if employed 300 days

150 Men if employed 230 days

Step-by-step explanation:

Total work done in 25 days by 150 men will be 150 a x 25 = 1/4  

                                                             a = 1/4 x 1/3750  

                                                             a = 1/15,000  

Therefore 100 men in 60 days = 100 x 60 a = 6000 a  

                                    So work = 6/15 = 2/5  

Now total work done = 1/4  + 2/5 = 13/20  

So remaining work will be = 1 – 13/20  

                                           = 7 / 20

Now remaining time = 130 – (25 + 60 + 10) = 35 days  

So 1/4  work is done in  25 days by 150 men  

Therefore work is done in 1 day by 150 x 4 x 25 = 15000  

Therefore  7/20 work is done in 35 days by    

So 15000 x 7 / 35 x 20 = 150 men