a contractor undertook to build a wall and employed 20 labourers to finish work in 24 das. after working 6 days, additional number of labourers were taken to finish the work in 18 days
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30- men work 20- days and complete 25% of work.
So (30 x 20)= 600 man- hours is required to complete 25% work.
So to complete the remaining 75% of work we require = (600 x4)= 1800 man-hours of work.
To complete the work in the remaining (60–20)= 40- days number of men required =1800/40 =45.
So additional workers required = (45–30)= 15
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