a contractor undertook to complete a work in 120 days.he employed 400 men.in 72 days only half of the work was done. How many more men should be employed to complete the work on time? solve with steps
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Answer:
56
Explanation:
Given, M1 = 120, M2 = 120-x,
D1 = 64, D2
W1 = 23 and W2=13
According to the formula,
M1D1W1= M2D2W2
=> 120×642/3=(120−x)×601/3
=> 120×642×60=(120-x)
=> (120-x)=64
x=120-64=56
Now, 56 men can be discharged to finish the work in time.
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