Question

A convergent lens of focal length 20cm and made of a material with refractive index 1.1 is immersed in water. The lens will behave as a?

Answer 1

Answer:

it will behave like a divergent lens when it is immersed in water

Explanation:

As per lens makers formula we know that

$\frac{1}{F} = (\mu - 1)(\frac{1}{R_1} - \frac{1}{R_2})$

so here we know

$F = 20 cm$

now when lens is immersed into water

$\frac{1}{F'} = (\frac{\mu}{1.33} - 1)(\frac{1}{R_1} - \frac{1}{R_2})$

so we will have

$\frac{1}{F'} = (\frac{1.1}{1.33} - 1)(\frac{1}{R_1} - \frac{1}{R_2})$

so here we can see that

$F' < 0$

so it will behave like a divergent lens when it is immersed in water

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Topic : Lens Maker's Formula

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