a converging and diverging lens of equal focal lengths are placed coaxially in contact find the focal length and power of the combination
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sum of powers=1/f+1/(-f)
=0
focal length of combination=1/F=0
then
F=1/0=infinity
=0
focal length of combination=1/F=0
then
F=1/0=infinity
Answered by
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Power of the combination is zero.
Focal length of combination is infinity.
Explanation:
Given, we have a converging and a diverging lens of equal focal lengths placed coaxially in contact.
Focal length of diverging lens (concave) = -f
Focal length of converging lens (convex) = f
Power of the combination = Focal length of converging lens + Focal length of diverging lens = f - f = 0
Power of the combination is zero.
Focal length of combination = 1 / (Focal length of converging lens) + 1 / (Focal length of diverging lens)
1/F = 1 / f + 1/(-f) = 1/f - 1/f = 0
Hence F = 1/0 which is infinity.
Focal length of combination is infinity.
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