Question

A converging lens forms a real image I on its optic axis. A rectangular glass slab of refractive index  and thickness t is introduced between the lens and I. I will move 1) away from the lens by t( 1)   2) towards the lens by t( 1)   3) away from the lens 1 t          4) towards the lens by 1 t        

Answer 1

Answer:

Explanation:

When a slab is placed here will be shift in position of image away from lens

Shift = t(1- 1/u)