A converging lens has a focal length of 25 cm. Calculate its power and express it according to sign convention.
Answers
Answer :
- power of given Converging lens is +4 Dioptre.
Explanation :
given that,
- focal length of converging lens is 25 cm; so,
f = + 25 cm
( because focal length of converging lens is always positive )
we need to find
- power of the converging lens
P = ?
Now,
As we know Power is known as the reciprocal of focal length in metres.
- P = 1 / f
[ where P is power of lens in Dioptre unit and f is focal length of lens in metres unit ]
so,
Converting focal length of given lens from cm unit to metre unit
→ f = 25 cm
→ f = 25 / 100 m
→ f = 0.25 m
Calculating power of the given lens
→ P = 1 / f
→ P = 1 / (0.25)
→ P = + 4 D
therefore,
- Power of the converging lens of focal length 25 cm is +4 Dioptre.
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- Power of the lens is defined as the degree of convergence or divergence of lens.
- Optical power is also known as the reciprocal of focal length of lens.
- SI unit of optical power : Dioptre (D)
- 1 Dioptre = m⁻¹
- Power = 1 / (focal length of lens)
- Dimension of optical power : [ kg⁰ s⁰ m⁻¹ ]
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✴ A converging lens has a focal length of 25 cm. Calculate its power and express it according to sign convention.
✒ It's Power according to the sign convention rule is +4 dioptre.
Given :-
- A converging lens.
- A focal length ( f ) 25 cm = 0.25 m.
To Find :-
- Its power and express it according to sign convention.
Calculation :-
A converging lens is also known as a convex lens .
- It converts parallel rays of light to convergent rays and produces a real image.
- The object is away from the focal point .
- The image formed is real and inverted.
We have our,
Focal length ( f ) as 0.25 m .
We know that the formulae of power of lens is
P =
Putting value,
➡ P =
➡ P =
➡ P = 4 D
S.I. unit of power is Dioptre (D) .
The sign convention for this is +4 D.
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