Physics, asked by kavinithya0605, 8 months ago

A converging lens has a focal length of 25 cm. Calculate its power and express it according to sign convention. ​

Answers

Answered by Cosmique
41

Answer :

  • power of given Converging lens is +4 Dioptre.

Explanation :

given that,

  • focal length of converging lens is 25 cm; so,

         f = + 25 cm

( because focal length of converging lens is always positive )

we need to find

  • power of the converging lens

        P = ?

Now,

As we know Power is known as the reciprocal of focal length in metres.

  • P = 1 / f

[ where P is power of lens in Dioptre unit and f is focal length of lens in metres unit ]

so,

Converting focal length of given lens from cm unit to metre unit

→ f = 25 cm

→ f = 25 / 100  m

f = 0.25 m

Calculating power of the given lens

→ P = 1 / f

→ P = 1 / (0.25)

P = + 4 D

therefore,

  • Power of the converging lens of focal length 25 cm is +4 Dioptre.

________________________

  • Power of the lens is defined as the degree of convergence or divergence of lens.
  • Optical power is also known as the reciprocal of focal length of lens.
  • SI unit of optical power : Dioptre (D)
  • 1 Dioptre =  m⁻¹
  • Power = 1 / (focal length of lens)
  • Dimension of optical power : [ kg⁰ s⁰ m⁻¹ ]

________________________

Answered by ıtʑFᴇᴇʟɓᴇãᴛ
26

\mathtt{\huge{\underline{\red{Question\:?}}}}

✴ A converging lens has a focal length of 25 cm. Calculate its power and express it according to sign convention.

\mathtt{\huge{\underline{\green{Answer:-}}}}

✒ It's Power according to the sign convention rule is +4 dioptre.

\mathtt{\huge{\underline{\pink{Solution:-}}}}

Given :-

  • A converging lens.

  • A focal length ( f ) 25 cm = 0.25 m.

To Find :-

  • Its power and express it according to sign convention.

Calculation :-

A converging lens is also known as a convex lens .

  • It converts parallel rays of light to convergent rays and produces a real image.

  • The object is away from the focal point .

  • The image formed is real and inverted.

We have our,

Focal length ( f ) as 0.25 m .

We know that the formulae of power of lens is

P =  \dfrac{1}{f}

Putting value,

➡ P =  \dfrac{1}{f}

➡ P =  \dfrac{1}{0.25}

➡ P = 4 D

S.I. unit of power is Dioptre (D) .

The sign convention for this is +4 D.

____________________________________

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