Question

A converging lens has focal length 20cm and object placed 50 cm from the lens will have an image at the location ? and the lateral magnification will be

Answer 1

Answer:

$\frac{100}{3} = v$

Explanation:

Given :

focal length = f = +20cm

object distance = u = -50cm

image distance = v = ?

Using lens formula,

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

Inserting the values in the equation,

$\frac{1}{20} = \frac{1}{v} - (\frac{1}{ - 50})$

$\frac{1}{20} = \frac{1}{v} + \frac{1}{ 50}$

$\frac{1}{20} - \frac{1}{50} = \frac{1}{v}$

$\frac{5 - 2}{100} = \frac{1}{v}$

$\frac{100}{3} = v$

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