A converging lens has focal length 250mm.calculate its power and express it according to sign conventions??????????
Answers
Answered by
59
focal length of the lens f =+250mm=250/1000
=+0.25cm
power of the lens P=1/f
P =1/0.25
P=+4D
=+0.25cm
power of the lens P=1/f
P =1/0.25
P=+4D
Answered by
18
Answer:
focal length=250mm=0.25m
power= 1/focal length
=1/0.25
=+4 D.
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