A converging lens of focal length 15 cm and a converging mirror of focal length 10 cm are placed 50 cm apart. If a pin of length 2.0 cm is placed 30 cm from the lens farther away from the mirror, where will the final image form and what will be the size of the final image?
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Given:
converging lens of focal length =f=15 cm
converging mirror of focal length =f=-10 cm
Distance between lens and mirror is 50cm
height of pin=ho=2cm
u=- 30cm
1/f=1v-1/u
1/v=1/f+1/u
1/v= 1/15 -1/30
=2-1/30
=1/30
v= 30cm
Nature of image:
- real
- inverted
- same size as object
This image is at a distance of 20cm from concave mirror which is formed at c.
Thus mirror forms the image with same size as object and at the same place
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Hope it helps-----
converging lens of focal length =f=15 cm
converging mirror of focal length =f=-10 cm
Distance between lens and mirror is 50cm
height of pin=ho=2cm
u=- 30cm
1/f=1v-1/u
1/v=1/f+1/u
1/v= 1/15 -1/30
=2-1/30
=1/30
v= 30cm
Nature of image:
real
inverted
same size as object
This image is at a distance of 20cm from concave mirror which is formed at c.
Thus mirror forms the image with same size as object and at the same place
converging lens of focal length =f=15 cm
converging mirror of focal length =f=-10 cm
Distance between lens and mirror is 50cm
height of pin=ho=2cm
u=- 30cm
1/f=1v-1/u
1/v=1/f+1/u
1/v= 1/15 -1/30
=2-1/30
=1/30
v= 30cm
Nature of image:
real
inverted
same size as object
This image is at a distance of 20cm from concave mirror which is formed at c.
Thus mirror forms the image with same size as object and at the same place
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