Question

A converging lens of refractive index 1.5 is kept in a liquid medium having same refractive index. What would be the focal length of the lens in this medium?

● Only hand typed answers
● No spams ​

Answer 1

Answer:

Hope it helps

Explanation:

mark me as branliest

Answer 2

Answer:

Infinity (∞)

Explanation:

Given :

refractive index 1.5; kept in a liquid medium having same refractive index

To Find :

the focal length of the lens in this medium

Solution :

We know that, according to the extension of lens makers formula,

$\huge{\frac{1}{f} = ( \frac{\mu_l}{\mu_m}-1) (\frac{1}{R_1} - \frac{1}{R_2} )}$

Where, f = Focal length of the lens in the medium

μl = refractive index of lens

μm = refractive index of medium

R₁ = Radius of first curvature

R₂ = Radius of second Curvature

Here, in this question it is mentioned that

$\mu_l = \mu_m$

So,

from the formula we get,

$\huge{\frac{1}{f} = ( 1-1) (\frac{1}{R_1} - \frac{1}{R_2} )}\\\huge{\frac{1}{f} = ( 0) (\frac{1}{R_1} - \frac{1}{R_2} )}\\\huge{\frac{1}{f} = 0\\ \implies \huge {f = \frac{1}{0} } \implies \huge{f = \infty }$

Hope it helps

Please mark as brainliest