Physics, asked by srivatsasubramp2howm, 1 year ago

A converging lens with a focal length of 15cm produces a magnification of -3 of an object placed in front of the lens. find the position and nature of the image.

Answers

Answered by rohitkumargupta
8
F=-15
Using the formula 1/u + 1/ v =1/f
M =-v/u =>v = 3u
Using lens formula,
1/u + 1 /3u = 1/-15
4u/3u²=1/-15
-15*4=3u*1
-60=3u
U=-20
And, v = 3 * - 20 =>-60(where - denotes the image is virtual and it is just behind the mirror.)
Hope its help you dude

Pharmitha: Converging lens should have focal length in positive
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