A converging lens with a focal length of 15cm produces a magnification of -3 of an object placed in front of the lens. find the position and nature of the image.
Answers
Answered by
8
F=-15
Using the formula 1/u + 1/ v =1/f
M =-v/u =>v = 3u
Using lens formula,
1/u + 1 /3u = 1/-15
4u/3u²=1/-15
-15*4=3u*1
-60=3u
U=-20
And, v = 3 * - 20 =>-60(where - denotes the image is virtual and it is just behind the mirror.)
Hope its help you dude
Using the formula 1/u + 1/ v =1/f
M =-v/u =>v = 3u
Using lens formula,
1/u + 1 /3u = 1/-15
4u/3u²=1/-15
-15*4=3u*1
-60=3u
U=-20
And, v = 3 * - 20 =>-60(where - denotes the image is virtual and it is just behind the mirror.)
Hope its help you dude
Pharmitha:
Converging lens should have focal length in positive
Similar questions