A convex lens formed as real and inverted image of a bject
at a distance of 25 cm from it. Where is the object placed in front
of the convex lens if the image is equal to the size of the bject?
Also find the power of the lens
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Answer:
Object distance, u= – 50 cm
Image distance, v= 50 cm
Focal length = f
According to the lens formula,
u = -50 cm
v = + 50 cm.
f =?
1/f = 1/v – 1/u
1/f = 2/50 = 1/25
f = 25cm
Power of the lens p = 1/f
P = 1/25cm-1
= 1/25(10-2m)-1
=100/25m-1 = 4m-1
1m-1 = 1D
P = 4D
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