A convex lens forms a real and inverted image of a needle at a distance of 50cm from it.where is the needle placed in front of the convex lens if the image is equal to the size of the object ?also,find the power of the lens...(reply fast )
Answers
v=+50cm u=? p=?
as image formed by the lens is real , inverted of the same size , implies object is at 2f so image is at 2f
u=2 f=50cm
f=50/2 = 25cm
p=100/f(cm)
p=100/25=4D ans.
Hey Happy Soul ❤
Your Answer :
The position of image should be at 2F, since the image is real and same size.
It is given that the image of the needle is formed at a distance of 50 cm from the convex lens.
Therefore, the needle is placed in front of the lens at a distance of 50 cm.
Focal length :
Object distance (u) = - 50 cm
Image distance, (v) = 50 cm
Focal length = f
According to the lens formula,
1/v - 1/u = 1/f
1/f = 1/50 - 1/(-50)
1/f = 1/50 + 1/50
1/f = 1/25
f = 25 cm = 0.25 m
Power of lens :
p = 1 / f ( in meter)
p = 1/0.25 = +4 D
Hope this will helps you ☺
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