A convex lens forms an erect and two times magnified image of an object placed at a distance 10cm in front of it.Find the position of the image.
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Answer:
A) the object is placed between f1and optic center
. b) the focal length could be found through lens formulae as magnification is +3.
+3u=v
1/f=1/v-1/u
=1/3u-1/u
=(1-3)/3u
=-2/3*-20(u =-20)
=f=15cm
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