a convex lens forms An erect image of an object placed at a distance of 15 cm from it. if the image formed is twice as big as the object find the :-
1) position of the object
2) focal length of the lens
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Answer:
focal length will be +30 cm
Explanation:
given that hi=2 ho
therefore hi/ho = v/u
putting values
2 ho/ho = v/-15
v = -30 cm
therfore image is virtual
using 1/f = 1/v - 1/u
therefore f=+30 cm
hope it helps
pls mark braunliest
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