A convex lens has focal length of 20cm. At what distance from the lens should the object be placed so that it forms a real and inverted image 40cm away from lens? What would be the size of the image formed if the object is 4cm high? With help of a ray diagram show the formation of the image by lens in this case
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before seeing my solution please see the sign convention attachment first.
object distance=u
image distance=v=40cm
focal length=20cm
according to lens formula
1/v-1/u=1/f
1/40-1/20=1/u
1/u=-1/40
u=-40
which means it is 40 cm away from lens in the left side at 2f.
Now
As image is real and inverted its height will be negative.=x
so height of object =4cm
magnification=v/u=x/4
=>40/-40=x/4
-4=x
height of image =4cm inverted.
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