A convex lens has focal length of 20cm in air. Find its focal length in water.
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Refractive index of glass w.r.t. air = μg
Refractive index of the liquid w.r.t. air = μl = 2μg
If a lens made of glass of refracive index μg is immersed in a liquid of refractive index μl then its focal length fl is given by
1fl=(μlg−1)×(1R1−1R2)
If f is the focal length of the lens in air then
120=(μag−1)×(1R1−1R2)
Therefore
fl20=(μag−1)(μ1g−1)
=(μag−1)(μagμal−1)
=(μg−1)(μgμl−1)
The liquid is water.
μl=μw=1.33
μg≈1.5>μw
fw20=(1.5−1)(1.51.33−1)
=0.5(1.13−1)=3.846fw=3.846×20
fw=76.92
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A convex lens has focal length of 20cm in air. Find its focal length in water.
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