Question

A CONVEX LENS HAVING RADIUS OF CURVATURE 30 CM

PRODUCED 3 TIMES ENLARGED REAL IMAGE . WHERE SHOULD

BE OBJECT PLACED.​

Answer 1

Answer:

As per the given conditions,

m = 3 {A concave mirror produces three times enlarged image of an object and the }

u = -10 cm

Formula

We know that,

[latex]m = \frac{-v}{u}[/latex]

Substituting the known values we get,

3 = (-v)/(-10)

v =  30

The distance between the mirror and image =   30 cm

From mirror formula, we know

[latex]\frac{1}{v}+\frac{1}{u}= \frac{1}{f}[/latex]

 

⇒ [latex]\frac{1}{30}+\frac{1}{-10}= \frac{1}{f}[/latex]

(-2)/30 = 1/f

or f = – 15

The radius of curvature R = 2f

∴ R = 2 × (- 15)

R = -30 cm

Explanation: