A CONVEX LENS HAVING RADIUS OF CURVATURE 30 CM
PRODUCED 3 TIMES ENLARGED REAL IMAGE . WHERE SHOULD
BE OBJECT PLACED.
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Answer:
As per the given conditions,
m = 3 {A concave mirror produces three times enlarged image of an object and the }
u = -10 cm
Formula
We know that,
[latex]m = \frac{-v}{u}[/latex]
Substituting the known values we get,
3 = (-v)/(-10)
v = 30
The distance between the mirror and image = 30 cm
From mirror formula, we know
[latex]\frac{1}{v}+\frac{1}{u}= \frac{1}{f}[/latex]
⇒ [latex]\frac{1}{30}+\frac{1}{-10}= \frac{1}{f}[/latex]
(-2)/30 = 1/f
or f = – 15
The radius of curvature R = 2f
∴ R = 2 × (- 15)
R = -30 cm
Explanation:
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