A convex lens having two curved surfaces with equal radii R is taken and object is placed at its center of curvature.The refractive index of the lens is n and the lens is placed in air then calculate the following 1.focal length of the lens .2. distance of the image formed .3. discuss nature of the image
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Lens maker's equation:
1/f = (n - 1) [1/R1 - 1/R2]
= (n - 1) [1/R + 1/R] = 2(n - 1) /R
f = R/ [2(n-1)]
1/v - 1/u = 1/f , u is -ve by convention.
1/v + 1/R = (n-1)2/R
1/v = (2n - 3)/R
v = R/(2n - 3)
m = v/u = 1/(2n - 3).
Nature of the image depends on the refractive index n of the lens. If it is less than 3/2, then it will form a virtual magnified image.
If the n > 3/2, then it will form a real magnified image.
1/f = (n - 1) [1/R1 - 1/R2]
= (n - 1) [1/R + 1/R] = 2(n - 1) /R
f = R/ [2(n-1)]
1/v - 1/u = 1/f , u is -ve by convention.
1/v + 1/R = (n-1)2/R
1/v = (2n - 3)/R
v = R/(2n - 3)
m = v/u = 1/(2n - 3).
Nature of the image depends on the refractive index n of the lens. If it is less than 3/2, then it will form a virtual magnified image.
If the n > 3/2, then it will form a real magnified image.
kvnmurty:
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Explanation:
nature of the image depends on the refractive index
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