Question

A convex lens is placed somewhere in between an object and a screen. The distance between the object
and screen is 48 cm. If the numerical value of the magnification produced by the lens is 3, focal length o
the lens is
[ ]
a) 16cm
b) 12cm
c) 9cm
d) 4.5cm​

Answer 1

Answer:

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Answer 2

Answer:

9 cm

Explanation:

Given that u+v=48 cm

Numerical value of m=3=vu⇒v=3u

Substituting in u+v=48 cm

We getu=12 cm, v=36 cm

By sign convention

u=−12 cm, v=+36 cm (real image formed)

We have 1v−1u=1f

⇒136+112=1f

∴f=9 cm