A convex lens is placed somewhere in between an object and a screen. The distance between the
object and screen is 48cm. If the numerical value of the magnification produced by the lens is 3, focal
length of the lens is
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Answer:
If we consider that the object is placed at a distance u from the lens, then object distance =−u
This gives, u+v=x
Also, magnification, m=
−u
−v
=
u
v
Now, using the lens formula,
v
1
−
−u
1
=
f
1
Solving these 3 equations simultaneously, we get:
f=
(m+1)
2
mx
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