Question

A convex lens of f=10 is placed at distancs of 12cm from wall

Answer 1

What we should find

Answer 2

HEY MATE

$\huge\mathfrak\green{Solution}$

$<b>$

f= 10cm

u=-12cm

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

$\frac{1}{v} = \frac{1}{f} + \frac{1}{u}$

$\frac{1}{v} = \frac{1}{10} + \frac{1}{ - 12} \\ = \frac{6 - 5}{60} = \frac{1}{60}$

v=60cm

The image will be formed in front of lens

Nature of image is real and inverted.

$<b><u><I>$

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