Physics, asked by devisriprasad521, 8 months ago

A convex lens of focal lenght 16cm forms a real image double the size of the object . The distance of the object from the lens is ?

Answers

Answered by Anonymous
68

GiveN :

  • Focal length (f) = 16 cm
  • Magnification (m) = 2

To FinD

  • Object Distance from lens

SolutioN :

Use formula for Magnification of lens :

m = v/u

⇒2 = v/u

⇒v = 2u ......(1)

Image position is twice that of object.

_______________________

Use lens formula for calculating object distance.

⇒1/f = 1/v - 1/u

Put value of v from (1)

⇒1/16 = 1/2u - 1/u

⇒1/16 = (1 - 2)/2u

⇒1/16 = -1/2u

⇒-2u = 16

⇒-u = 16/2

⇒-u = 8

⇒u = - 8

\therefore Object is placed at distance of 8 cm from lens.

Answered by Reshma1806
10

Answer:

The object is placed at a distance of 8 cm from the lens.

Explanation:

Given that,

Focal length of a convex lens, f = +16 cm

The lens forms a real image double the size of the object, the magnification of the lens is 2.

To find,

The object distance.

Solution,

The magnification of a lens is given by :

v = 2u

Now using lens formula as :

On solving the above equation, we get :

u = -8 cm

So, the object is placed at a distance of 8 cm from the lens.

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