Question

A convex lens of focal length 10cm is placed at a distance of 15cm from a wall.How far frim the lebs and the object be placed so as toform a real image on the wall also find magnification?
plzzz answer this question .....
of class10th​

Answer 1

Answer:

Focal length (f ) = -15 cm

Distance of image (v) = -10 cm

\(\frac{1}{v} – \frac{1}{u} = \frac{1}{f}\)

1/u = -(1/10) – (1/- 15)

1/u =1/15 – 1/10

1/u = -0.033

u = -30 cm

so the object is placed 30 cm away from the concave lens.

Ray diagram