a convex lens of focal length 20 cm forms a virtual image of height 1 cm at a distance of 16 cm behind the mirror. what is the height of the object?
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Answer:
MARK BRAINLIST
Explanation:
Let H’ = Height of object
H= Height of image.
Then , H = 2 H’
M ( magnification ) = -V / U ….. (1.)
Also, M = H / H’ ….. (2.)
Combining 1 and 2
- V / U = 2H’ / H’
- V / U = 2
U = - V / 2
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