A convex lens of focal length 20cm is mounted on an upright of an
optical bench. The image of a distant object is formed on a screen.
A concave lens of focal length25cm is placed in contact with the
given lens. The screen is moved suitably to focus the image of
the same distant object.
a. What is the distant of screen from convex lens, where image of distant object is
obtained?
b. How does the combination of lenses behave?
c. Where will the image of distant object be formed?
d. Will the image formed by combination be real or virtual?
e. What is the formula for magnification obtained with a lens?
Answers
Answered by
2
Explanation:
Image of a distant object is formed at the focus.
The image due to first lens is formed at 20 cm. Hence, f
1
=20cm
The image due to combined lens is formed at 40/3 cm. Hence, f
eq
=
3
40
f
eq
=
f
1
+f
2
f
1
f
2
⇒f
eq
=
20+f
1
20×f
1
=
3
40
3f
1
=40+2f
1
f
1
=40cm
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Answered by
1
Answer:
Good morning Rahul ❤️
Have a great day Ahead ^_^
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