A convex lens of focal length 25 cm in tact with a covex lens of focal length 20cm
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focal length of concave lens = -25 cm = -25 /100 m power = P₁ = 1/-25/ 100 = -4 D
focal length of convex lens = +20 cm = 20/100 m power = P₂ = 1/20/100 = 5 D
So net power = P = P₁ + P₂ = -4 D + 5D = 1 D (implies combination behave as convex lens).
Hope this solution is correct
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