A convex lens of focal length 2m has an object placed at
a distance of 0.5 m from it. The image formed is
(1) Real, at a distance of 2/3 m from the lens
(2) Virtual, at a distance of 2/3 m from the lens
(3) Real, at a distance of 0.4 m from the lens
(4) Virtual, at a distance of 0.4 m from the lens
with full explanation and no spaming pls
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Given, f = 2
u = - 0.5 m
v = ?
Lens formula
1/f = 1/v - 1/u
1/v = 1/f + 1/u
1/v = 1/2 + 1/-0.5
1/v = 1/2 - 1/0.5
1/v = -3/2
[ v = - 2/3] ans
2. Image is Virtual and Erect at a distance 2/3 from the lens
u = - 0.5 m
v = ?
Lens formula
1/f = 1/v - 1/u
1/v = 1/f + 1/u
1/v = 1/2 + 1/-0.5
1/v = 1/2 - 1/0.5
1/v = -3/2
[ v = - 2/3] ans
2. Image is Virtual and Erect at a distance 2/3 from the lens
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