A convex lens of focal length 2m has an object placed at
a distance of 0.5 m from it. The image formed is
(1) Real, at a distance of 2/3 m from the lens
(2) Virtual, at a distance of 2/3 m from the lens
(3) Real, at a distance of 0.4 m from the lens
(4) Virtual, at a distance of 0.4 m from the lens
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Answer:
Based on the info given, the magnification produced will be, m and −m
Hence,
u
1
=f(1+
m
1
)
u
2
=f(1−
m
1
)
Eliminating m from the 2 equations we get,
f=
2
u
1
+u
2
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