Physics, asked by dinesh275530, 3 months ago

A convex lens of focal length 3cm is placed between a screen and a square plate of area 4 cm^2 . The image formed on the screen is 16cm^2. Calculate the distance between plate and the screen​

Answers

Answered by ritamriyu123
2

Given: A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing object or the screen, we again get a real image on the screen which is 9 cm long. 

Given: A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing object or the screen, we again get a real image on the screen which is 9 cm long. To find the length of the object

Given: A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing object or the screen, we again get a real image on the screen which is 9 cm long. To find the length of the objectSolution:

Given: A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing object or the screen, we again get a real image on the screen which is 9 cm long. To find the length of the objectSolution:Let the height of the object be h1

Given: A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing object or the screen, we again get a real image on the screen which is 9 cm long. To find the length of the objectSolution:Let the height of the object be h1At the first position, 

Given: A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing object or the screen, we again get a real image on the screen which is 9 cm long. To find the length of the objectSolution:Let the height of the object be h1At the first position, m1=h14=−uv

Given: A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing object or the screen, we again get a real image on the screen which is 9 cm long. To find the length of the objectSolution:Let the height of the object be h1At the first position, m1=h14=−uvAt the second position, 

Given: A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing object or the screen, we again get a real image on the screen which is 9 cm long. To find the length of the objectSolution:Let the height of the object be h1At the first position, m1=h14=−uvAt the second position, m2=h19=−vu

Given: A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing object or the screen, we again get a real image on the screen which is 9 cm long. To find the length of the objectSolution:Let the height of the object be h1At the first position, m1=h14=−uvAt the second position, m2=h19=−vuNow, m=m1×m2⟹(−uv)×(−vu)=h14×h19⟹h12=36⟹h1=6cm

Given: A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing object or the screen, we again get a real image on the screen which is 9 cm long. To find the length of the objectSolution:Let the height of the object be h1At the first position, m1=h14=−uvAt the second position, m2=h19=−vuNow, m=m1×m2⟹(−uv)×(−vu)=h14×h19⟹h12=36⟹h1=6cmHence the length of the object should be 6 cm.

hope it helps

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