a convex lens of focal length 40 cm and a concave lens of focal lenght 50 cm are placed in contact with each other.(i) calculate the power of lens (ii) the focal lenght of the lens combination
Answers
Answered by
57
convex lens f = +40 cm as the principal focal point is in the direction of the rays.
concave lens = -50 cm as the principal focal point is on the side of the object.
combination of thin lenses: 1/f = 1/f1 + 1/f2 = 1/40 - 1/50 = 1/200
f = 200 cm positive so convex lens
P1 = 1 /(40/100) meter = 2.5 Dioptre
P2 = 1/(-50/100)m = -2 D
power of combination = P = P1 + P2 = 2.5 - 2.0 = 0.5 D
or, 1/(200/100)m = 1/2 = 0.5 D
concave lens = -50 cm as the principal focal point is on the side of the object.
combination of thin lenses: 1/f = 1/f1 + 1/f2 = 1/40 - 1/50 = 1/200
f = 200 cm positive so convex lens
P1 = 1 /(40/100) meter = 2.5 Dioptre
P2 = 1/(-50/100)m = -2 D
power of combination = P = P1 + P2 = 2.5 - 2.0 = 0.5 D
or, 1/(200/100)m = 1/2 = 0.5 D
Answered by
25
convex lens f = +40 cm
concave lens = -50 cm
combination of thin lenses:
1/f = 1/f1 + 1/f2 = 1/40 - 1/50 = 1/200
f = 200 cm positive so convex lens
P1 = 1 /(40/100) meter = 2.5 Dioptre
P2 = 1/(-50/100)m = -2 D
power of combination = P = P1 + P2 = 2.5 - 2.0 = 0.5 D
concave lens = -50 cm
combination of thin lenses:
1/f = 1/f1 + 1/f2 = 1/40 - 1/50 = 1/200
f = 200 cm positive so convex lens
P1 = 1 /(40/100) meter = 2.5 Dioptre
P2 = 1/(-50/100)m = -2 D
power of combination = P = P1 + P2 = 2.5 - 2.0 = 0.5 D
Similar questions