Question

A convex lens of focal length 50 cm and a concave lens having half the focal length of convex lens are placed in close contact with each other.calculate the lens power of this combination​

Answer 1

Answer:

Solution:

$P_{convex1} = \frac{100}{50} = +2D$

$P_{concave1} =\frac{100}{-50} = -2D$

$P_{concave2} = \frac{100}{-20} = -5D$

$P_{eq}= - 2 -5+2$

$= -5 D$

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Explanation: