Physics, asked by munna2411, 11 months ago

A convex lens of focal length f is placed in between an object and a screen at a distance d

Answers

Answered by jagadishojha
5

[mx / (m + 1)2]

Explanation:

Given: x = u + v and m = (v/u)  ∴ x = u + mu = u(m + 1)  ∴ u = [x / (m + 1)] and v = [mx / (m + 1)]  we know  (1/f) = (1/v) + (1/u)  ∴ (1/f) = [1 / {mx / (m + 1)}] + [1 / {x / (m + 1)}]  ∴ (1/f) = [(m + 1) / mx] + [(m + 1) / x]  ∴ (1/f) = [{(m + 1) + m(m + 1)} / mx]  ∴ (1/f) = [{(m + 1)(1 + m)} / mx] = [(m + 1)2 / mx]  ∴ f = [mx / (m + 1)2]

Hope this answer is correct

Answered by Anonymous
4

A convex lens of focal length f is placed somewhere in between an object and a screen. The distance between the object and the screen is x. If the numerical value of the magnification produced by the lens is m, then the focal length of the lens is:

(a) mx / (m+1)²

(b) mx / (m-1)²

(c) (m+1)²x /m

(d) (m-1)²x /m

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