A convex lens of power 2D is placed at a distance of 40 cm from a wall .At what distance from the lens should candle placed so that its image formed on the wall?
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Answer ⤵
- 200 cm is the required answer .
Explanation:
Given:-
- Power of lens ,P = 2 D
- Object distance ,u = -40 cm
To Find:-
- Image distance ,v
Solution:-
Firstly we calculate the focal length of the lens. As we know the relationship between Focal length and Power .
• P = 1/f
Substitute the value we get
→ 2 = 1/f
→ 2f = 1
→ f = 1/2
→ f = 0.5 m
→ f = + 50 cm
Now,
Using lens formula
• 1/v - 1/u = 1/f
Substitute the value we calculate
→ 1/50 = 1/v - 1/(-40)
→ 1/50 = 1/v + 1/40
→ 1/v = 1/50 - 1/40
→ 1/v = 4-5/200
→ 1/v = -1/200
→ v = -200 cm
- Hence, the image distance is 200 cm .
Hope it's helpful
:)
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