A convex lens of refractive index 1.5 has a focal length of 18 cm in air.
Calculate the change in its focal length when it is immersed in water of refractive
index.
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refractive index of lens ß=1.5
focal length in air f=18cm
refractive index of water is ß'=1.3
according to lenz makers formula,
f1/f=ß-1/(ß/ß' -1)
or, f1=(1.5-1)/(1.1378-1)×f
focal length in water f1=3.9*18=72cm
focal length in air f=18cm
refractive index of water is ß'=1.3
according to lenz makers formula,
f1/f=ß-1/(ß/ß' -1)
or, f1=(1.5-1)/(1.1378-1)×f
focal length in water f1=3.9*18=72cm
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